Teslim is designing a cover for a book. He wants to have a rectangular grid with x^2 – 10x + 21 squares in it, for some positive whole number x. What are the possible side lengths for the grid? A. (x – 3) and (x – 7)
B. (x – 3) and (x + 7)
C. There are no possible whole number side lengths.
D. (x + 3) and (x + 7)

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

step-by-step explanation:

its 512 because parenthesis and to the 2nd power is 512 so it will be 512

25/6

step-by-step explanation:

you multiply 4 by the denominator (4*6=24) and add it to the numerator which makes it 25/6.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: