X and Y are mathematically similar chocolate boxes. Y
X has a volume of 130 cm^3 and a surface area of 202^2 cm?.
The volume of Y is 638.69 cm^3.
What is the surface area of Y?

992.43 cm²

Step-by-step explanation:

From the question given above, the following data were obtained:

Volume of shape X (Vₓ) = 130 cm³

Surface area of shape X (SAₓ) = 202 cm²

Volume of shape Y (Vᵧ) = 638.69 cm³

Surface area of shape Y (SAᵧ) =?

The surface area of shape Y can be obtained as follow:

Since the shape are similar, then:

Vₓ / Vᵧ = SAₓ / SAᵧ

130 / 638.69 = 202 / SAᵧ

Cross multiply

130 × SAᵧ = 638.69 × 202

130 × SAᵧ = 129015.38

Divide both side by 130

SAᵧ = 129015.38 / 130

SAᵧ = 992.43 cm²

Thus, surface area of shape Y is 992.43 cm²

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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