Determine the center and radius of the following circle equation: x² + y2 + 2x – 2y – 62 = 0​

Step-by-step explanation:

x²+2x+y²-2y=62

using completing the square

x²+2x+1+y²-2y+1=62+1+1

(x+1)²+(y-1)²=64

(x+1)²+(y-1)²=8²

(x-a)²+(y-b)²=r²

by comparison

(a,b)=(-1,1)

a,b is the center of the circle

r=8unit

r is the radius

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}