In ΔJKL, the measure of ∠L=90°, JK = 5.8 feet, and LJ = 4.4 feet. Find the measure of ∠K to the nearest degree.

39

Step-by-step explanation:

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\cos J = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{72}{93}

cosJ=  

hypotenuse

adjacent

​  

=  

93

72

​  

\cos J = \frac{72}{93}

cosJ=  

93

72

​  

J=\cos^{-1}(\frac{72}{93})

J=cos  

−1

(  

93

72

​  

)

J=39.268\approx 39^{\circ}

J=39.268≈39  

∘

Type into calculator and round to the nearest degree.

J

K

L

72

93

(adjacent to ∠J)

(opp. of ∠J)

(hypotenuse)

39°

:expert answer!

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

what are you trying to solve here

step-by-step explanation: