Can you help me please ​

9514 1404 393

  240

Step-by-step explanation:

The generic k-th term of the expansion of the binomial ...

  (a +b)^n

is given by ...

  (nCk)a^(n-k)b^k . . . . . where nCk = n!/(k!(n-k)!) and 0 ≤ k ≤ n

For this problem, we have ...

  a=2x, b=y, n=6, k=2

Then the 2nd term (counting from 0) is ...

  6C2×(2x)^4×y^2 = (6·5)/(2·1)·16x^4·y^2

  = 240x^4y^2

The desired coefficient is 240.

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Additional comment

The coefficients for the expansion match the numbers in a row of Pascal's triangle. The row beginning with 1, n will have the coefficients for the expansion to the n-th power.

I’m vary good with science if you need with that

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)