Find the 96th term of the arithmetic sequence-30,-32,34

a = -30

d = -32 - (-30) = -2

n = 96

So, using A.P. formula-

Tn = a + (n-1) d

T96 = -30 + (96-1) -2

T96 = -30 + (95) -2

T96 = -30 - 190

T96 = -220

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arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.