Joe's company has shipping crates that are too small. If they make a crate double in length, width and height, how many times greater is the volume of the new crate? O 2​

8 times greater

Step-by-step explanation:

The volume of a crate is calculated by multiplying the length, width, and height together. Let's assume that the original values for these were 2, 2, and 2 inches. We can multiply them together to get the volume of the original crate.

2 * 2 * 2 = 8

The new crate is double the value of every side, which would be 4, 4, and 4 inches. Let's multiply these values to get the volume of the new crate...

4 * 4* 4 = 64

Now that we have both volumes we can divide the volume of the new crate by the volume of the old crate to calculate how many times greater the new crate's volume is

64 / 8 = 8 times greater

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a