These are fill in the blanks. 1. When I use line segments to connect the corresponding points of a pre-image and the image in a translation, the line segments are and because .
2. When I use line segments to connect the corresponding points of a pre-image and the image in a reflection, the line of reflection is the of the segments because .
3. In a rotation, the corresponding points of the pre-image and the image are the same from the center of rotation because .
4. Translations, rotations, and reflections are rigid motion transformations because .

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2