John has 6 pairs of pants and 3 shirts. How many possible outfits consisting of one shirt and one pair of pants can he select?

4*5*7=140 ways

Step-by-step explanation:

First he has to decide on a pair of pants and he has 4 different choices.

For each of those choices he has a choice of 7 different shirts, so that gives him 4 times 7 = 28 different pant/shirt combinations. (I hope none of the pants are striped and none of the shirts have polka-dots).

For each those 28 possibilities, he has 5 different ties he could select, so altogether he has 28 times 5 = 140 different outfits, and some of them may be acceptable to wear in public.

It is simply , 4*5*7=140 ways.

tayeserqp p201311

so mark-up is 0.4 multiplied by 180 = 72