Mr Thompson, This is my homework! Please help.

Problem 1

There's not much to say about these. You'll just have to memorize the terms. Note with standard form that the exponents decrease as you move from left to right (2,1,0).

Problem 2

Other names for zeros are:

The term "root" is also applicable here.

Problem 3

We set each piece equal to 0 and solve for x. This is the zero product property

f(x) = (x-2)(x+4)

0 = (x-2)(x+4)

(x-2)(x+4) = 0

x-2 = 0 or x+4 = 0

x = 2 or x = -4

The two x intercepts are located at (2,0) and (-4,0)

Choice C

Problem 4

In the last problem, we found the two roots were x = 2 and x = -4

I'll let p = 2 and q = -4.

Average the roots to get (p+q)/2 = (2+(-4))/2 = -2/2 = -1

This is the x coordinate of the vertex. So h = -1

Plug this into the function to find k, which is the y coordinate of the vertex.

k = f(h)

k = f(-1)

k = (-1-2)(-1+4)

k = (-3)(3)

k = -9

The vertex is located at (h,k) = (-1, -9)

This is another way of saying the vertex is when x = -1 and y = -9

Choice C