A graph with horizontal axis time (seconds) and vertical axis position (meters). An orange line runs straight upward from 0 second zero meters. A concave blue line runs upward from the same point. Maia says that both lines on this position vs time graph show acceleration. Is she correct? Why or why not?
the answer is
Maia is not correct because a straight line moving upwards on a position vs time graph has a constant slope, so it represents constant velocity. No change in velocity means no acceleration is taking place. so please injoy ur day

idk

step-by-step explanation:

b. b < 1 might be the correct answer

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could