Braxton has money in a savings account. The equation B = 800(1 + 0.03) can be used to calculate the amount of money in dollars, B. Braxton has in his account after t years since opening the account.

Pam also has money in a savings account. The equation P=800(1 +0.04) can be used to calculate the

amount of money in dollars, P, Pam has in her account after t years since opening the account.

Choose from the drop down menus to correctly complete each sentence.

Braxton's initial investment Choose...

• Pam's initial investment.

The interest on Braxton's account Choose...

• the interest on Pam's account.

Braxton's initial investment is equals to (=) Pam's initial investment.

The interest on Braxton's account is less than (< ) the interest on Pam's account.

Step-by-step explanation:

Given - Braxton has money in a savings account. The equation

            B = can be used to calculate the amount of money    

           in dollars, B, Braxton has in his account after t years since opening

           the account.

           Pam also has money in a savings account. The equation

           P=  can be used to calculate the  amount of money in

           dollars, P, Pam has in her account after t years since opening the

           account.

To find - Braxton's initial investment ..........Pam's initial investment.

             The interest on Braxton's account .....the interest on Pam's account.

Proof -

As given, Broxton equation is -

               Pam equation is -  

Now,

1.)

For initial investment , Put t = 0

⇒B =

  P =  

As for t = 0

Braxton's equation , B = Pam's equation,P

⇒Braxton's Initial investment = Pam's initial investment.

2.)

For the interest,

As we don not have time for which the interest has to be check.

So , let the time period = 5 years

Therefore,

B =

P =  

Now,

Interest on Braxton's account = 927.42 - 800 = 127.42 ≈ 127

Interest on Pam's account = 973.32 - 800 = 173.32 ≈ 173

∴ we get

The interest on Braxton's account is less than the interest on Pam's account.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest