The Food Marketing Institute shows that 17\%17% of households spend more than $$100$ per week on groceries. Assume the population proportion is p = .17p=.17 and a simple random sample of 800800 households will be selected from the population. a. Show the sampling distribution of \bar{p} pˉ , the sample proportion of households spending more than $$100$ per week on groceries.
b. What is the probability that the sample proportion will be within \pm .02±.02 of the population proportion?
c. Answer part (b) for a sample of 16001600 households.

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

50- 250 is correct i did that one too

step-by-step explanation:

what chart am i supposed to follow?