Arectangle’s length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w?

If the width is w, then the length can be defined as 2w+5.

The area can be found using lxw, and we can substitute in our length to get w(2w+5).

Expand to get 2w^2+5y

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.