Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation. (4,−3); y=3x−5

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4

Idon't take stuff like this new to me