In ΔMNO, the measure of ∠O=90°, the measure of ∠M=74°, and OM = 5.4 feet. Find the length of NO to the nearest tenth of a foot.

18.8 feet

Step-by-step explanation:

\tan M = \frac{\text{opposite}}{\text{adjacent}}=\frac{x}{5.4}

tanM=

adjacent

opposite

​

=

5.4

x

​

\tan 74=\frac{x}{5.4}

tan74=

5.4

x

​

5.4\tan 74=x

5.4tan74=x

Cross multiply.

x=18.832\approx \mathbf{18.8}\text{ feet}

x=18.832≈18.8 feet

Type into calculator and roundto the nearest tenth of a foot.

M

N

O

5.4

18.8

(adjacent to ∠M)

(opp. of ∠M)

(hypotenuse)

74°

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy