Mathematics, 01.03.2021 01:30 dondre54

given that the root of the quadratic equation 2x^2 + 6x -3x =0 are alpha(a) and beta (b) where a is greater than b evaluate a.{√(a^2 - b^2)} b. (a^2/b) - (b^2/a)

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given that the root of the quadratic equation 2x^2 + 6x -3x =0 are alpha(a) and beta (b) where a is greater than b evaluate a.{√(a^2 - b^2)} b. (a^2/b) - (b^2/a)​

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given that the root of the quadratic equation 2x^2 + 6x -3x =0 are alpha(a) and beta (b) where a is greater than b evaluate a.{√(a^2 - b^2)} b. (a^2/b) - (b^2/a)