An assembly worker is making 3-legged and 5-legged stools. She has 67 legs to use in all for the day's work. What is the largest number of 3- legged stools she can make and still use all the legs to make 5-legged stools with the rest of the legs?

Step-by-step explanation:

let number of 5 legs=x

so 67-5x =multiple of 3

x=1,67-5=62 not divisible by 3

x=2,67-5×2=57 ÷3=19

so he can make 19 three -legged table and 2 five -legged table.

the answer is n

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°