For all values of x, f(x)=2x+1 and g(x)=x^2 Solve fg(x)=gf(x)

Im not exactly sure

but you have to substitute

so

fg(x)=2x^2+1

gf(x)=(2x+1)^2

4x^2+4+2

2x^2+1=4x^2+4x+1

1=2x^2+4x+1

0=2x^2+4x+2

the solve i think

x = 0, -2

Step-by-step explanation:

4x^2+4x+1= 2x^2+1

2x^2+4x=0

Solve for x using the quadratic formula:

x = 0, x = -2

it would open into a square depending on the type of envelope i’m not sure about the second part