In ΔSTU, s = 6.1 cm, t = 3.2 cm and u=7.4 cm. Find the measure of ∠S to the nearest 10th of a degree.

m∠S = 54.1°

Step-by-step explanation:

Use the law of cosines

37.21 = 10.24 + 54.76 - 47.36 cos S

-27.79 = -47.36 cos S

.586782 = cos S

arccos .586782 = S

m∠S = 54.1°

answer: 1 2 3 6

step-by-step explanation:

1x6=6 2x3=6

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3