One airplane is 78 miles due south of a control tower. Another airplane is 52 miles from the control tower at a heading of N 38 degrees E. To the nearest tenth of a mile, how far apart are the two airplanes?

123.2 miles

Step-by-step explanation:

Given that One airplane is 78 miles due south of a control tower. Another airplane is 52 miles from the control tower at a heading of N 38 degrees E. To the nearest tenth of a mile, how far apart are the two airplanes?

The angle Ø = 90 + 52 = 142 degree

Or 180 - 28 = 142 degree

Using cosine formula

D^2 = 78^2 + 52^2 - 2(78)(52)Cos142

D^2 = 6084 + 2704 - 8112Cos142

D^2 = 8788 + 6392.34

D^2 = 15180.34

D = 123.2 miles

Therefore, the two planes are 123.2 miles apart.

is means division by fractions

step-by-step explanation:

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12