David spots a plane at an angle of elevation of 35 degrees. If he is 2650 feet from the plane, what is the altitude of the plane?

1,519.98 feet

Step-by-step explanation:

Given the following

Angle of elevation = 35 degrees

Distance of david from the plane = 2650feet

Altitude = x

Using SOH CAH TOA

sin theta = opp/hyp

sin 35 = x/2650

x = 2650sin35

x = 2650(0.5736)

x = 1,519.98

Hence the altitude of the plane is 1,519.98 feet

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.