Mathematics, 26.02.2021 22:10 lilspike420

Jonathan’s lunch account began with $50 and he spends $2.25 per day on his lunch. Nelson’s lunch account began with $13 and he spends $0.40 per day on his lunch. Which equation could be used to solve how many day, d, Jonathan and Nelson will have the same amount of money in their lunch accounts? Answer Choices-
50−2.25d=13−0.40d50 minus 2 point 2 5 d is equal to 13 minus 0 point 4 0 d

50+2.25d=13+0.40d50 plus 2 point 2 5 d is equal to 13 plus 0 point 4 0 d

50d−2.25= 13d−0.4050d−2.25= 13d−0.40

50d+2.25=13d+0.40

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Jonathan’s lunch account began with $50 and he spends $2.25 per day on his lunch. Nelson’s lunch acc...