1. For the function f(x) = x2, Find the slope of the secant line joining (1,f(1)) and (1.01, f(1.01))

Please solve with an explanation please

idrk the answer im very sorry

Step-by-step explanation:

The slope of the line connecting two points (a, b) and (c, d) is

(d - b) / (c - a)

i.e. the change in the y-coordinate divided by the change in the x-coordinate. For a function y = f(x), this slope is the slope of the secant line connecting the two points (a, f(a) ) and (c, f(c) ), and has a value of

(f(c) - f(a) ) / (c - a)

Here, we have

f(x) = x ²

so that

f (1) = 1² = 1

f (1.01) = 1.01² = 1.0201

Then the slope of the secant line is

(1.0201 - 1) / (1.01 - 1) = 0.0201 / 0.01 = 2.01

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

step-by-step explanation:

your mom