The sum of three numbers is 41. The third number is five more than three-fourths of the second number. If the first number is half of the second number, what is the value of the third number?

Step-by-step explanation:

Givens

Let the first number be x / 2

Let the second number = x

Let the third number = 3/4 x + 5

Equation

x/2 + x + 3/4 x + 5 = 41                    Multiply through by 4

Solution

2x + 4x + 3x + 20 = 164                  Combine like terms on the left

9x + 20 = 164                                  Subtract 20 from both sides.

9x + 20 - 20 = 164 - 20

9x = 144                                           Divide by 9

9x/9 = 144/9

x = 16

Answer

The first number is 16/2 =                          8

The second number is   =                         16

The Third number = 3/4*16+ 5 = 12 + 5 = 17

The sum =                                                  41

dunno

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft