(2x² + 6x + 10) + (4x² + 2x + 3)

How to solve your question

Your question is

(

2

2

+

6

+

1

0

)

+

(

4

2

+

2

+

3

)

(2x^{2}+6x+10)+(4x^{2}+2x+3)

(2x2+6x+10)+(4x2+2x+3)

Simplify

1

Eliminate redundant parentheses

(

2

2

+

6

+

1

0

)

+

(

4

2

+

2

+

3

)

2

2

+

6

+

1

0

+

4

2

+

2

+

3

2

Add the numbers

3

Combine like terms

4

Combine like terms

Solution

6

2

+

8

+

1

3

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92