The path of a toy rocket fired into the air can be represented by the equation h= -16t^2+75t. What is the height of the rocket after 3 seconds?

81 units

Step-by-step explanation:

Given data

We are given the function for the height, the height is a function of time t

h=-16t^2+75t

Hence for t= 3 , let us substitute and find the height h

h=-16(3)^2+75(3)

h= -16*9+ 225

h= -144+ 225

h= 81

Hence the height at 3 seconds is 81 units

the answer is c just got it on ed

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.