The perimeter of a triangle is 53 meters. Side a is three less than side b and side c is twice side b.

a = 11

b = 14

c = 28

Step-by-step explanation:

a+b+c = 53

b-3 = a

c = 2b

substitute for a and c

(b-3)+b+(2b) = 53

reduce

4b-3 = 53

add 3 to each side

4b = 56

divide both sides by 4

b = 14

a = 14-2 = 11

c = 2(14) = 28

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

a. she will receive a refund of $278.

step-by-step explanation: