The least squares regression equation for the data in the table is ỹ = 13.5x + 58.4. The R-value is 0.977.
х
у
0
65
2.
82
4
107
6
134
8
174
Why might you use a linearized model instead?

answer: the answer is ann

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

ok thats very interesting