What is the equation of the parabola that has a vertex at (3,1) and passes through point (2,-1)? Explain the answer

Step-by-step explanation:

Down-opening parabola with vertex (3,1):

y = a(x-3)^2+1

(2,-1) is a point on the parabola.

-1 = a(2-3)^2 +1

a = -2

y = -2(x/3)^2 + 1

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1