A farmer has chickens, sheep and horses there are 154 animals and 516 total legs the number of sheep equals twice the number of chickens how many of each type of animals does he have

number of chicken = 50

number of sheep = 100

number of horse = 4

Step-by-step explanation:

Let

x = number of chicken

y = number of sheep

z = number of horse

x + y + z = 154 (1)

2x + 4y + 4z = 516 (2)

the number of sheep equals twice the number of chickens

y = 2x

Substitute into the equation

x + y + z = 154

x + 2x + z = 154

3x + z = 154 (3)

2x + 4y + 4z = 516

2x + 4(2x) + 4z = 516

2x + 8x + 4z = 516

10x + 4z = 516 (4)

3x + z = 154 (3)

10x + 4z = 516 (4)

Multiply (3) by 4 to eliminate z

12x + 4z = 616 (5)

10x + 4z = 516 (4)

Subtract (4) from (5)

12x - 10x = 616 - 516

2x = 100

x = 100/2

x = 50

Recall,

y = 2x

y = 2(50)

y = 100

x + y + z = 154

50 + 100 + z = 154

150 + z = 154

z = 154 - 150

z = 4

number of chicken = 50

number of sheep = 100

number of horse = 4

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.