I need step by step answers pleass
Systems of Equations
4x-3y=-20
-x-8y=5

(-5, 0)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Distributive Property

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Algebra I

Terms/CoefficientsCoordinates (x, y)Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

4x - 3y = -20

-x - 8y = 5

Step 2: Rewrite Systems

-x - 8y = 5

[Addition Property of Equality] Add 8y on both sides:                                   -x = 8y + 5[Division Property of Equality] Divide -1 on both sides:                                 x = -8y - 5

Step 3: Redefine Systems

4x - 3y = -20

x = -8y - 5

Step 4: Solve for y

Substitution

Substitute in x:                                                                                                  4(-8y - 5) - 3y = -20[Distributive Property] Distribute 4:                                                                 -32y - 20 - 3y = -20Combine like terms:                                                                                         -35y - 20 = -20[Addition Property of Equality] Add 20 on both sides:                                  -35y = 0[Division Property of Equality] Divide -35 on both sides:                              y = 0

Step 5: Solve for x

Define original equation:                                                                                 -x - 8y = 5Substitute in y:                                                                                                  -x - 8(0) = 5Multiply:                                                                                                             -x = 5[Division Property of Equality] Divide -1 on both sides:                                 x = -5

Where’s the stuff st? ? lol sorry