The dimensions of a pet carrier is 20 inches
long, 11 3/4 inches wide, and 11 1/2 inches
high...
Mathematics, 25.02.2021 23:20 egyptforrest9892
The dimensions of a pet carrier is 20 inches
long, 11 3/4 inches wide, and 11 1/2 inches
high. What is the volume of the pet carrier?
Answers: 3
Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
Mathematics, 21.06.2019 22:00, zurfluhe
Manuela claims that and are congruent. which statement best describes her claim? she is incorrect because the segments do not have the same orientation. she is incorrect because the segments do not have the same length. she is correct because the segments have the same length. she is correct because the segments have the same orientation.
Answers: 1
English, 21.10.2020 19:01