Mathematics, 25.02.2021 21:50 haftjnd9156
We can now solve 1 + u = ±Ket2/2 + 6t for u. u = −1 ± Correct: Your answer is correct. , where K > 0 Notice that u = −1 is a solution. This means that K could also be 0. Since we now know that K ≥ 0 we can let A represent any arbitrary constant and replace ±K with +A to create a more simplified equation. So we could simply write
Answers: 2
Mathematics, 21.06.2019 17:30, andrewjschoon2876
Which equation represents a line that is parallel to the line whose equation is 3x-2y=7( show all work)
Answers: 3
Mathematics, 21.06.2019 21:30, allendraven89pds755
Which equation is true? i. 56 ÷ 4·7 = 82 ÷ (11 + 5) ii. (24 ÷ 8 + 2)3 = (42 + 9)2 neither i nor ii ii only i and ii i only
Answers: 1
Mathematics, 21.06.2019 21:50, Animallover100
What is the missing reason in the proof? segment addition congruent segments theorem transitive property of equality subtraction property of equality?
Answers: 3
Mathematics, 21.06.2019 23:00, tfyvcu5344
The weight of a radioactive isotope was 96 grams at the start of an experiment. after one hour, the weight of the isotope was half of its initial weight. after two hours, the weight of the isotope was half of its weight the previous hour. if this pattern continues, which of the following graphs represents the weight of the radioactive isotope over time? a. graph w b. graph x c. graph y d. graph z
Answers: 2
We can now solve 1 + u = ±Ket2/2 + 6t for u. u = −1 ± Correct: Your answer is correct. , where K >...
Spanish, 23.06.2019 08:00
Biology, 23.06.2019 08:00
Mathematics, 23.06.2019 08:10