Read the following scenarios and indicate the type of reliability in each scenario. Explain your answers i) Test-retest reliability
ii) Parallel forms reliability
iii) Internal consistency reliability
iv) Interrater reliability
a) You want to evaluate the reliability of a critical thinking assessment. You create a large set of items that all pertain to critical thinking and then randomly split the questions into two sets of questionnaires. You administer both versions of the test to the same group of individuals. The scores from the two versions can then be correlated in order to evaluate the consistency of results across alternate versions.
b) You want to evaluate the degree to which the art portfolios in your 7th grade class meets the required standards. You ask 3 different art experts to evaluate the students' portfolios with the help of a rubric.
c) You are developing a math measure to test the constructs of number sense and logic of your 4th grade students. You want to make sure your measure is not testing other constructs like arithmetic skills. You would like to evaluate the degree to which different test items that probe the same constructs produce similar results.

The Type of Reliability in each Scenario are:

Scenario   Type of Reliability Test

a)               Parallel forms reliability

b)               Interrater reliability

c)               Internal consistency reliability

Step-by-step explanation:

Types of Reliability Tests:  

Test-retest reliability = measures the results consistency with the application of the same test at different times.

Interrater reliability = shows consistent ratings by different examiners.

Parallel formsreliability = uses alternative versions of an equivalent test to probe for similar results.

Internal consistency reliability = this test checks the consistency of individual items of a test.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.