A school cafeteria makes 4 different salads during the week but serves only 2 each day on a rotating basis. The 4 salads are listed below. • Chicken (C)
• Fruit (F)
• Pasta (P)
• Tuna (T)

Part A: Use the letters C, F, P, and T to list all outcomes of 2 salads.

Part B: A student randomly chooses a day to buy a cafeteria salad without knowing which 2 salads are being served. What is the probability the student chooses a day the cafeteria is serving chicken salad, pasta salad, or both? Show your work or explain your thinking.

Question 1 options:

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part A

CF,CP, CT, FP, FT, PT

Part B

The cafeteria  serves chicken salad , pasta salad or both for 5 of 6 possible combinations so the probability will be 5/6 or about 0.83 or 83%

Step-by-step explanation:

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5/6

Step-by-step explanation:

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

a. 19,958,400

step-by-step explanation:

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