Mathematics, 25.02.2021 06:40 colexie7410

PLEASE HELP! a. How many 7-digit numbers have odd numbers in the odd positions (i. e. odd numbers in the first, third, fifth and seventh positions)? (2)

b. How many of these have even numbers in the even positions?

PLEASE HELP! a. How many 7-digit numbers have odd numbers in the odd positions (i.e. odd numbers in

Answers: 1

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Answer from: alextoro

a) 625,000

b) 78,125 if 0 is counted as even or 40,000 if it is not.

Step-by-step explanation:

Represent the 7 digit number by abcdefg

Position Allowable digits Number of allowable digits

g 1,3,5,7,9 5

f 0,1,2,3,4,5,6,7,8,9 10

e 1,3,5,7,9 5

d 0,1,2,3,4,5,6,7,8,9 10

c 1,3,5,7,9 5

b 0,1,2,3,4,5,6,7,8,9 10

a 1,3,5,7,9 5

This implies that the number of 7 digit numbers with odd digits in the odd positions is

5x10x5x10x5x10x5=625000

For part b, count 0 as an even digit. Then rule out 1,3,5,7,9 in positions b, d, and f. This leaves 5 possible digits in all 7 locations. So the answer is

5^7=78,125

If 0 is not counted as an even digit, then the answer is

4^3+5^4=40000

Answer from: Quest

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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PLEASE HELP! a. How many 7-digit numbers have odd numbers in the odd positions (i. e. odd numbers in...