Triangle TVW is dilated according to the rule DO,3/4(x, y)(three-fourths x, three-fourths y) to create the image triangle T'V'W', which is not shown.

On a coordinate plane, triangle T V W has points (negative 4, 8), (0, 4), and (4, 4).

What are the coordinates of the endpoints of the segment T'V'?

T'(-3, 6) and V'(0, 3)
T'(-3, 6) and V'(0, 1)
T'(-1, 2) and V'(0, 3)
T'(-1, 2) and V'(0, 1)

add the table and i will answer correctly

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

step-by-step explanation:

no solution.