Solve algebraically the simultaneous equations

x^2+y^2=25
y-3x=13

In the form of (x,y) there are 2 solutions:

(-3,4)

(-24/5, -7/5)

Step-by-step explanation:

First isolate one of the letters (for me I'm using the y of equation 2 because it's easier to solve)

Now that we have y isolated, substitute y in equation 1 with the equation we got previously (y=13+3x)

Now simplify:

Now turn the equation into ax^2+bx+c=0 form by transferring 25 to the other side of the equation:

Using the quadratic formula we will have the 2 following values:

Substitute the following values into any equation you want (this time I'll pick equation 2 again since its the easiest to solve)

not sure but it may be b, as i said i'm not sure.