![subject](/tpl/images/cats/mat.png)
Mathematics, 24.02.2021 02:30 RyleyM
77 7/8% into a fraction
![ansver](/tpl/images/cats/User.png)
Answers: 1
![](/tpl/images/ask_question.png)
![](/tpl/images/ask_question_mob.png)
Other questions on the subject: Mathematics
![image](/tpl/images/cats/mat.png)
Mathematics, 21.06.2019 14:30, jadaroyval
Is fgh ~ jkl? if so, identify the similarity postulate or theorem that applies.
Answers: 1
![image](/tpl/images/cats/mat.png)
![image](/tpl/images/cats/mat.png)
Mathematics, 22.06.2019 00:10, angelteddy033
Use your knowledge of the binary number system to write each binary number as a decimal number. a) 1001 base 2= base 10 b) 1101 base 2 = base 10
Answers: 1
![image](/tpl/images/cats/mat.png)
Mathematics, 22.06.2019 02:00, AnastasiaJauregui
If p(x) is the total value of the production when there are x workers in a plant, then the average productivity of the workforce at the plant is a(x) = p(x) x . (a) find a'(x). a'(x) = xp'(x) − p(x) x a'(x) = xp'(x) − p(x) x2 a'(x) = p'(x) − p(x) x a'(x) = xp'(x) − p'(x) x2 a'(x) = p'(x) − xp(x) x2 why does the company want to hire more workers if a'(x) > 0? a'(x) > 0 ⇒ a(x) is ; that is, the average productivity as the size of the workforce increases. (b) if p'(x) is greater than the average productivity, which of the following must be true? p'(x) − xp(x) > 0 p'(x) − xp(x) < 0 xp'(x) − p'(x) > 0 xp'(x) − p(x) < 0 xp'(x) − p(x) > 0
Answers: 2
You know the right answer?
77 7/8% into a fraction...
Questions in other subjects:
![Konu](/tpl/images/cats/himiya.png)
Chemistry, 09.12.2020 23:30
![Konu](/tpl/images/cats/istoriya.png)
History, 09.12.2020 23:30
![Konu](/tpl/images/cats/himiya.png)
Chemistry, 09.12.2020 23:30
![Konu](/tpl/images/cats/mat.png)
![Konu](/tpl/images/cats/mkx.png)
![Konu](/tpl/images/cats/mat.png)
![Konu](/tpl/images/cats/obshestvoznanie.png)
Social Studies, 09.12.2020 23:30
![Konu](/tpl/images/cats/mat.png)
Mathematics, 09.12.2020 23:30
![Konu](/tpl/images/cats/mat.png)
![Konu](/tpl/images/cats/geografiya.png)
Geography, 09.12.2020 23:30