1. Write a quadratic equation that can be solved by factoring. Solve your equation and show and explain all your work. 2. In this unit you have learned about several different ways to solve quadratic equations. How do you determine which method to use when you’re trying to solve a quadratic equation?

Step-by-step explanation:

1. - 2x - 15 = 0

Then we look for two factors whose product gives -15, and sum equals -2x.

The factors are; -5x and 3x.

So that,

+ 3x - 5x  - 15 = 0

( + 3x)(-5x -15)

x (x + 3) -5 (x + 3)

(x + 3)(x - 5)

Then,

x + 3 = 0

x = -3

Also,

x - 5 = 0

x = 5

The roots of the equation are: x = -3 or 5.

2. When solving question quadratic equation, the values of the coefficients of the variable and the constant are first considered. The relationship among them would give the clue on which method to use in solving the question.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6