Find the equation of a line parallel to −5x+y=2 that contains the point (5,−2). Write the equation in slope-intercept form.

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

Step-by-step explanation:

Parallel lines have same slopes.

Line 1,   L1:  5x-2y=20   is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.

5x-2y = 20

-2y = -5x+20

y = (-5/-2)x+20/(-2)

y = (5/2)x-10 hence m1=5/2 and y-intercept is -10

Line 2 , L2:   y-y1 = m (x-x1),  m=m2=m1=5/2

Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2

L2: y-0 = 5/2(x-5)

y = 5/2x-25/2

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