A composite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base lengths of 10 centimeters and 6 centimeters, and a height of 4 centimeters. Trapezoid area: A = one-half (b 1 + b 2) h What is the area of this composite figure? 32 centimeters squared 40 centimeters squared 64 centimeters squared 80 centimeters squared Mark this and return

Option C: is the area of the composite figure.

Step-by-step explanation:

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

and

Area of the trapezoid =

Substituting the values, we get,

Thus, the area of one trapezoid is

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure =

Thus, the area of the composite figure is

Hence, Option C is the correct answer.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4