What’s 8367 divided by 7

1195.28

Step-by-step explanation:

We have a division problem which is 8,367 ÷ 7.

When it comes to division, you always look at the first number that is being split equally by the second number.

Follow the steps of the division problem :

Find how many times 7 goes into 8 :

7 * 1 = 7

Subtract 7 from 8 :

8 - 7

1

We have 1 in our thousands place, move down the number next to 8 in 8367 which is 3, and see how many times 7 goes into that number :

13

7 * 1 = 7

Therefore 7 only goes in once, put 1 next to 1 on top of the division problem, subtract 7 from 13 :

13 - 7

6

Move the 6 down from 8367 and see how many times 7 goes into that :

7 * 9 = 63

Subtract 63 from 66 :

3

Put 9 next to the one, as for now we have 119, now bring down the last value in 8367 and see how many times 7 goes into that :

37

7 * 5

35

Subtract 37 - 35 :

2

Therefore, our answer is 1195.28 , 1195 Remainder 2

Step-by-step explanation: The result of 8367/7 is a non-terminating, repeating decimal. The repeating pattern above, 285714, is called repetend, and denoted overlined with a vinculum.

This notation in parentheses is also common: 8367/7 = 1195.(285714): However, in daily use it’s likely you come across the reptend indicated as ellipsis: 8367 / 7 = 1195.285714… .

8367 divided by 7 in decimal = 1195.285714

8367 divided by 7 in fraction = 8367 divided 7

8367 divided by 7 in percentage = 119528.57142857%

If it is okie can i have brainliest? it took me a while to write all of this.=3

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.