Factorise 343m^3 + 27n^3​

m3+27n3

Step-by-step explanation:

Rewrite

27

n

3

as

(

3

n

)

3

.

m

3

+

(

3

n

)

3

Since both terms are perfect cubes, factor using the sum of cubes formula,

a

3

+

b

3

=

(

a

+

b

)

(

a

2

−

a

b

+

b

2

)

where

a

=

m

and

b

=

3

n

.

move it to the other side

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.