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Mathematics, 23.02.2021 04:00 kony345p
X^2-4x+1=0
Here is what I have so far:
-1= -1
-4/2= -2, (-2)^2=4
x^2-4x+4=3
(x-2)(x-2)=3
(x-2)^2=3
√(x-2)^2= √3
I guess my real question is what is the root square and what is x.
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Answers: 3
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You know the right answer?
X^2-4x+1=0
Here is what I have so far:
-1= -1
-4/2= -2, (-2)^2=4
x^2-4x+4=3
...
-1= -1
-4/2= -2, (-2)^2=4
x^2-4x+4=3
...
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