0.3409 = 34.09% probability that under 70% color their hair in a group of 85 older women.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the Central Limit Theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](/tpl/images/1138/4945/21d7f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation
.
72% report that they color their hair to hide their gray.
This means that ![\mu = p = 0.72](/tpl/images/1138/4945/2448a.png)
What is the probability that under 70% color their hair in a group of 85 older women?
For a sample of 85, we have that ![s = \sqrt{\frac{0.72*0.28}{85}} = 0.0487](/tpl/images/1138/4945/e96b8.png)
This probability is the pvalue of Z when X = 0.7. So
![Z = \frac{X - \mu}{\sigma}](/tpl/images/1138/4945/21d7f.png)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](/tpl/images/1138/4945/d7db3.png)
![Z = \frac{0.7 - 0.72}{0.0487}](/tpl/images/1138/4945/1aa90.png)
![Z = -0.41](/tpl/images/1138/4945/78f86.png)
has a pvalue of 0.3409
0.3409 = 34.09% probability that under 70% color their hair in a group of 85 older women.