What is the solution set of the quadratic inequality 4(x + 2)^2 <= 0? {x| X=-2}
{x| X e R}
{x| X= 2}
ø

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

you would need to also lose 1 point for each of the other outcomes for it to be fair.

step-by-step explanation:

answer:

1.14285714286

step-by-step explanation:

divide 40 into 35 and you will get your answer