Write a polynomial function in standard form with the given zeros 1. -1, 3, 4

2. -3, 0, 0, 5

3. -2 multiplicity 3

4. (x+3)^2(x+1)​

Step-by-step explanation:

(x+1)(x-3)(x-4) = (x+1)(x²-7x+12) = x³-6x²+5x+12

(x+3)(x-0)(x-0)(x-5) = (x+3)(x²)(x-5) = (x²-2x-15)x² = x⁴-2x³-15x²

(x+2)³ = x³ + 3·x²·2 + 3·x·2² + 2³ = x³ + 6x² + 12x + 8

(x+3)²(x+1) = (x²+6x+9)(x+1) =  x³ + 7x² + 15x + 9

idk this answer sorry cant on this one.

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.