1. Given a circle (C) of center 0, of diameter [AB) and radius R. On (AB) and to the exterior of (C) we take a point C such that BC = AB2 Wedras threaga
ICP) to the circle: Pis the point of tangency
LeL M be the foot of the perpendicular drawn through B DE
The perpendicular to (AC) through C cuts (BM) at N
how do we draw it​

Hmmm i had this before , give me a sec

The answer would be $68.04

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )